KB0020 - Sort Processes by Resource Usage
I have had the requirement before to list the resources processes used on a Linux box. I found the following script online but could not get the original author's details. So, if this is yours, please reach out
Usage
./python3.6 sum_process_resources.py
Output
0. /opt/atom/atom | 27.8
1. /usr/lib/chromium-browser/chromium-browser | 11.2
2. python3.6 | 11.0
3. /opt/google/chrome/chrome | 1.6
4. /usr/lib/xorg/Xorg | 1.4
5. /opt/Franz/franz | 0.7
== MEM% ==
0. /usr/lib/chromium-browser/chromium-browser | 37.2
1. /opt/google/chrome/chrome | 11.3
2. /opt/Franz/franz | 10.6
3. /opt/atom/atom | 10.1
4. /usr/lib/xorg/Xorg | 2.0
5. com.google.android.gms.persistent | 1.4
== RSS MB ==
0. /usr/lib/chromium-browser/chromium-browser | 1475.07 MB
1. /opt/google/chrome/chrome | 461.35 MB
2. /opt/Franz/franz | 429.04 MB
3. /opt/atom/atom | 402.18 MB
4. /usr/lib/xorg/Xorg | 78.53 MB
5. com.google.android.gms.persistent | 58.02 MB
Code
#sum_process_resources.py
from collections import OrderedDict
import subprocess
def run_cmd(cmd_string):
"""Runs commands and saves output to variable"""
cmd_list = cmd_string.split(" ")
popen_obj = subprocess.Popen(cmd_list, stdout=subprocess.PIPE)
output = popen_obj.stdout.read()
output = output.decode("utf8")
return output
def sum_process_resources():
"""Sums top X cpu and memory usages grouped by processes"""
ps_memory, ps_cpu, ps_rss = {}, {}, {}
top = 6
output = run_cmd('ps aux').split("\n")
for i, line in enumerate(output):
cleaned_list = " ".join(line.split())
line_list = cleaned_list.split(" ")
if i > 0 and len(line_list) > 10:
cpu = float(line_list[2])
memory = float(line_list[3])
rss = float(line_list[5])
command = line_list[10]
ps_cpu[command] = round(ps_cpu.get(command, 0) + cpu, 2)
ps_memory[command] = round(ps_memory.get(command, 0) + memory, 2)
ps_rss[command] = round(ps_rss.get(command, 0) + rss, 2)
sorted_cpu = OrderedDict(sorted(ps_cpu.items(), key=lambda x: x[1], reverse=True))
sorted_memory = OrderedDict(sorted(ps_memory.items(), key=lambda x: x[1], reverse=True))
sorted_rss = OrderedDict(sorted(ps_rss.items(), key=lambda x: x[1], reverse=True))
print("==== CPU% ====")
for i, k in enumerate(sorted_cpu.items()):
if i < top:
print("{}. {} | {}".format(i, k[0], k[1]))
print("==== MEM% ====")
for i, k in enumerate(sorted_memory.items()):
if i < top:
print("{}. {} | {}".format(i, k[0], k[1]))
print("==== RSS MB ====")
for i, k in enumerate(sorted_rss.items()):
if i < top:
print("{}. {} | {} MB".format(i, k[0], round((k[1]/1024), 2)))
if __name__ == '__main__':
sum_process_resources()
#sum_process_resources.py
from collections import OrderedDict
import subprocess
def run_cmd(cmd_string):
"""Runs commands and saves output to variable"""
cmd_list = cmd_string.split(" ")
popen_obj = subprocess.Popen(cmd_list, stdout=subprocess.PIPE)
output = popen_obj.stdout.read()
output = output.decode("utf8")
return output
def sum_process_resources():
"""Sums top X cpu and memory usages grouped by processes"""
ps_memory, ps_cpu, ps_rss = {}, {}, {}
top = 6
output = run_cmd('ps aux').split("\n")
for i, line in enumerate(output):
cleaned_list = " ".join(line.split())
line_list = cleaned_list.split(" ")
if i > 0 and len(line_list) > 10:
cpu = float(line_list[2])
memory = float(line_list[3])
rss = float(line_list[5])
command = line_list[10]
ps_cpu[command] = round(ps_cpu.get(command, 0) + cpu, 2)
ps_memory[command] = round(ps_memory.get(command, 0) + memory, 2)
ps_rss[command] = round(ps_rss.get(command, 0) + rss, 2)
sorted_cpu = OrderedDict(sorted(ps_cpu.items(), key=lambda x: x[1], reverse=True))
sorted_memory = OrderedDict(sorted(ps_memory.items(), key=lambda x: x[1], reverse=True))
sorted_rss = OrderedDict(sorted(ps_rss.items(), key=lambda x: x[1], reverse=True))
print("==== CPU% ====")
for i, k in enumerate(sorted_cpu.items()):
if i < top:
print("{}. {} | {}".format(i, k[0], k[1]))
print("==== MEM% ====")
for i, k in enumerate(sorted_memory.items()):
if i < top:
print("{}. {} | {}".format(i, k[0], k[1]))
print("==== RSS MB ====")
for i, k in enumerate(sorted_rss.items()):
if i < top:
print("{}. {} | {} MB".format(i, k[0], round((k[1]/1024), 2)))
if __name__ == '__main__':
sum_process_resources()